The given equation can be rewritten as x5−5x3+4x=0. Since the polynomial expression on the left has no constant term, it has x as a factor: x(x4−5x2+4)=0. The expression in parentheses is a quadratic equation in x2 that can be factored, giving x(x2−1)(x2−4)=0. This further factors as x(x−1)(x+1)(x−2)(x+2)=0. The solutions for x are x=0,x=1,x=−1,x=2, and x=−2. Since it is given that x>0, the possible values of x are x = 1 and x = 2. Either 1 or 2 may be gridded as the correct answer.