This question can be answered by making a connection between the table and the algebraic equation. Each row of the table gives a value of x and its corresponding values in both w(x) and t(x). For instance, the first row gives x=1 and the corresponding values w(1)=−1 and t(1)=−3. The row in the table where x=2 is the only row that has the property x=w(x)+t(x):2=3+(−1). Therefore, choice B is the correct answer Choice A is incorrect because when x=1, the equation w(x)+t(x)=x is not true. According to the table, w(1)=−1 and t(1)=−3. Substituting the values of each term when x=1 gives −1+(−3)=1, an equation that is not true. Choice C is incorrect because when x=3, the equation w(x)+t(x)=x is not true. According to the table, w(3)=4 and t(3)=1. Substituting the values of each term when x = 3 gives 4 + 1 = 3, an equation that is not true. Choice D is incorrect because when x=4, the equation w(x)+t(x)=x is not true. According to the table,w(4)=3 and t(4)=3. Substituting the values of each term when x=4 gives 3+3=4, an equation that is not true.