The first equation can be rewritten as
y–x=3 and the second as
+y=3, which implies that
−x= , and so
x=0. The ordered pair (0, 3) satisfies the first equation and also the second, since 0 + 2(3) = 6 is a true equality.
Alternatively, the first equation can be rewritten as
y=x+3.
Substituting x + 3 for y in the second equation gives
+2(x+3)=6.
This can be rewritten using the distributive property as
+2x+6=6. It follows that
2x+x/2 must be 0. Thus, x = 0. Substituting 0 for x in the equation
y=x+3 gives y = 3. Therefore, the ordered pair (0, 3) is the solution to the system of equations shown.