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SSC CGL Model Paper 15
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© examsnet.com
Question : 70
Total: 100
The distance between places U and V is 1008 km. An express train leaves place U at 9:00 a.m. and runs at a speed of 126 km/hr. The train stops on the way for 20 minutes. At what time (in p.m.) the train will reach at the place V?
6
:
50
3
:
50
4
:
20
5
:
20
Validate
Solution:
Distance = 1008 km
Speed = 126 km /hr
Time taken
=
1008
126
=
8
hr
Train stops on the way for 20 min
So,Train will reach at = 9.00 am + 8 hr 20 min = 5.20 PM
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