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SSC CGL Model Paper 19
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© examsnet.com
Question : 54
Total: 100
ABCD is a square of side length 8 units M is a mid point of DC. Find the radius of circle
12
−
√
5
cm
12
−
4
√
3
cm
10
−
4
√
5
cm
12
−
4
√
3
cm
Validate
Solution:
Δ EMC is similar to Δ EAB
as MC || AB
MC
AB
=
1
2
⇒
EB
=
16
cm
MC
=
4
cm
AB
=
8
cm
EA
=
√
256
+
64
=
8
√
5
cm
Inradius of triangle
=
(
EB
+
AB
−
EA
)
2
Inradius
=
12
−
4
√
5
cm
© examsnet.com
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