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SSC CGL Tier-1 17-08-2017 Shift 1 Solved Paper
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© examsnet.com
Question : 64
Total: 100
The 3rd and 9th term of an arithmetic progression are - 8 and 10, respectively. What is the 16th term ?
34
28
25
31
Validate
Solution:
Let a be the first term and d be the common difference of an A.P.
Then, according to the question,
A
3
=
a
+
(
3
−
1
)
d
⇒
−
8
=
a
+
2
d
...(i)
and
A
9
=
a
+
(
9
−
1
)
d
⇒
10
=
a
+
8
d
... (ii)
On solving Eqs. (i) and (ii),
a
=
−
14
and
d
=
3
∴
A
16
=
a
+
(
16
−
1
)
d
=
−
14
+
(
15
)
×
3
=
−
14
+
45
=
31
© examsnet.com
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