SSC CGL Tier-1 18-Aug-2021 Shift 2 Solved Paper

Given, (A+B) 's 1 day work
=‌

1

20

. . . (i)
(B+C) 's 1 day work =‌

1

24

. . . (ii)
By Eqs. (i) and (ii), (A−C) 's 1 day work
=‌

1

20

−‌

1

24

=‌

6−5

120

=‌

1

120

Let C 's 1 day work =‌

1

2x

The, A's 1 day work =‌

1

x

According to the question,
‌

1

x

−‌

1

2x

‌‌=‌

1

120

⇒‌‌‌

2−1

2x

‌‌=‌

1

120

⇒‌‌x‌‌=60
Then, A's 1 day work =‌

1

60

and C's 1 day work =‌

1

120

Put the value of A in Eq. (i), we get
B's 1 day work
‌‌=‌

1

20

−‌

1

60

=‌

3−1

60

‌‌=‌

2

60

=‌

1

30

Now, 100% of work completed by B
=30 days
∴40% of work completed by B
‌‌=‌

40

100

×30
‌‌=12‌ days ‌