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SSC CGL Tier-1 20-Aug-2021 Shift 2 Solved Paper
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© examsnet.com
Question : 63
Total: 100
Two pipes
A
and
B
can fill an empty tank in
10
h
and
16
h
, respectively. They are opened alternately for
1
h
each, opening pipe
B
first. In how many hours, will the empty tank be filled?
14
2
5
16
2
5
10
2
5
12
2
5
Validate
Solution:
ln
1
h
, part filled by pipe
A
=
1
10
In
1
h
, part filled by pipe
B
=
1
16
Now, In 2 h, part filled
=
1
10
+
1
16
=
13
80
In
12
h
, part filled
=
13
×
6
80
=
78
80
Remaining part
=
1
−
78
80
=
2
80
=
1
40
∴
1
40
part filled by pipe
B
=
1
40
1
16
5
=
2
5
h
Hence, total time take by pipe
A
and
B
=
(
12
+
2
5
)
h
=
12
2
5
h
© examsnet.com
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