π(21)3cu.cm Volume of cylindrical rod =πR2H=πR2×7cu.cm. πR2×7=
4
3
π×21×21×21 ⇒R2=
4
3
×
21×21×21
7
∴R=√4×21×21=2×21 = 42 cm. Surface area of sphere =4πr2=4π(21)2 Total surface area of the rod =πR(R+H) = 2π × 42 (42 + 7) = 2π × 42 × 49 sq. cm. ∴ Required ratio =