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SSC CGL Tier 2 Exam 12 Jan 2017 Paper 1
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© examsnet.com
Question : 95
Total: 100
The angles of depression of two ships from the top of a light house are 60° and 45° towards east. If the ships are 300 metre apart, the height of the light house is
200
(
3
+
√
3
)
meter
250
(
3
+
√
3
)
meter
150
(
3
+
√
3
)
meter
160
(
3
+
√
3
)
meter
Validate
Solution:
(3)
AB = Lamp post = h metre
C and D = Positions of ships
CD = 300 metre; BC = x metre
∠ACB = 60 metre; ∠ADB = 45°
In ΔABC,
tan
60
°
=
A
B
B
C
⇒
√
3
=
h
x
⇒
h
=
√
3
x
In ΔABD,
tan
45
°
=
A
B
B
D
⇒
1
=
h
x
+
300
⇒
h
=
x
+
300
⇒
h
=
h
√
3
+
300
⇒
h
−
h
√
3
=
300
⇒
√
3
h
−
h
√
3
=
300
⇒
h
(
√
3
−
1
)
=
300
√
3
⇒
h
=
300
(
√
3
)
√
3
−
1
=
300
√
3
(
√
3
+
1
)
(
√
3
−
1
)
(
√
3
+
1
)
=
300
(
3
+
√
3
)
2
=
150
(
3
+
√
3
)
meter
© examsnet.com
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