(1) On putting x = 0 in x + y = 2, 0 + y = 2 ⇒ y = 2 ∴ Point of intersection on yaxis = (0, 2) Again, putting y = 0 in x + y = 2, x = 2 ∴ Point of intersection on xaxis = (2, 0) x – y = 0 will pass through origin and be equally inclined to axes.
On putting x = y in x + y = 2, 2y = 2 ⇒ y = 1 ∴ CD = 1 OA = 2 Area of ΔOAC=