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SSC CGL Tier 2 Exam 21 Sep 2014 Paper
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© examsnet.com
Question : 42
Total: 100
In a ΔABC, ∠B = p 3 , ∠C =
π
4
and D divides BC internally in the ratio 1 : 3 then
sin
∠
B
A
D
sin
∠
C
A
D
is equal to
1
√
2
1
√
3
1
√
6
√
6
Validate
Solution:
(3)
∠
B
=
π
3
,
∠
=
π
4
and
B
D
D
C
=
1
3
From ΔABD,
B
D
sin
B
A
D
=
A
D
sin
A
B
D
⇒
B
D
sin
B
A
D
=
A
D
sin
π
3
⇒
A
D
=
√
3
2
.
B
D
sin
B
A
D
.
.
.
(
i
)
From ΔADC,
C
D
sin
D
A
C
=
A
D
sin
A
C
D
⇒
C
D
sin
D
A
C
=
A
D
sin
π
4
⇒
A
D
=
1
√
2
.
C
D
sin
D
A
C
.
.
.
(
i
i
)
From equations (i) and (ii),
√
3
2
.
B
D
sin
B
A
D
=
1
√
2
.
C
D
sin
D
A
C
⇒
sin
B
A
D
sin
D
A
C
=
√
3
2
1
√
2
×
B
D
C
D
⇒
sin
B
A
D
sin
D
A
C
=
√
3
2
×
√
2
×
1
3
=
1
√
2
×
√
3
=
1
√
6
© examsnet.com
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