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SSC CGL Tier 2 Exam 25 Oct 2015 Paper 1
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© examsnet.com
Question : 45
Total: 100
The base of a right pyramid is a square of side 10 cm. If the height of the pyramid is 12 cm, then its total surface area is
400 cm
2
460 cm
2
260 cm
2
360 cm
2
Validate
Solution:
(4)
Slant height
=
B
E
=
√
12
2
+
5
2
=
√
144
+
25
=
√
169
=
13
c
m
∴ Lateral surface of pyramid
=
1
2
×
perimeter
of
base
×
slant
height
=
1
2
×
40
×
13
=
260
sq. cm
Area of base = 10 × 10 = 100 sq. cm.
∴ Total surface area = (260 + 100) sq. cm. = 360 sq. cm
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