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SSC CHSL 11 Aug 2021 Shift 2 Solved Paper
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Section:
Quantitative Aptitude
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© examsnet.com
Question : 56
Total: 100
x
,
y
are two positive numbers such that
x
>
y
. If
x
4
+
y
4
=
706
and
x
y
=
15
, then the value of
2
x
+
3
y
is
19
20
18
15
Validate
Solution:
Given,
x
4
+
y
4
=
706
∵
(
x
2
+
y
2
)
2
=
x
4
+
y
4
+
2
x
2
y
2
[
∵
(
a
+
b
)
2
=
a
2
+
b
2
+
2
a
b
]
⇒
(
x
2
+
y
2
)
2
=
706
+
2
×
(
15
)
2
[
∵
x
y
=
15
(given)
]
⇒
(
x
2
+
y
2
)
2
=
706
+
450
=
1156
x
2
+
y
2
=
√
1156
=
34
Now,
(
x
+
y
)
2
=
x
2
+
y
2
+
2
x
y
=
34
+
2
×
15
=
64
∴
x
+
y
=
8
. . .(i)
nd
(
x
−
y
)
2
=
x
2
+
y
2
−
2
x
y
=
34
−
2
×
15
=
4
∴
x
−
y
=
2
. . . (ii)
On solving Eqs. (i) and (ii);
x
=
5
and
y
=
3
∴
2
x
+
3
y
=
2
×
5
+
3
×
3
=
10
+
9
=
19
© examsnet.com
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