Let the two numbers be x and y and x>y. ∴ According to the question, x−y=5 . . . (i) and x3−y3=1850 . . . (ii) ∴x3−y3=(x−y)3+3xy(x−y) 1850=(5)3+3xy×5 [∵ from Eqs. (i) and (ii) ] xy=115 Now, we know, (x−y)2=x2+y2−2xy ∴(5)2=x2+y2−2×115 ⇒x2+y2=255 ∴(x+y)2=x2+y2+2xy =255+2×115 x+y=√485 . . . (iii) From Eqs. (i) and (iii); (x−y)(x+y)=5×√485 (x2−y2)=5√485