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SSC CHSL 12 Aug 2021 Shift 3 Solved Paper
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© examsnet.com
Question : 67
Total: 99
If
x
+
1
x
=
√
13
, then one of the values of
x
3
−
1
x
3
is
4
√
11
32
4
√
13
36
Validate
Solution:
Given,
x
+
1
x
=
√
13
∴
(
x
−
1
x
)
2
=
(
x
+
1
x
)
2
−
4
=
(
√
13
)
2
−
4
=
13
−
4
=
9
⇒
(
x
−
1
x
)
=
√
9
=
3
We know that,
x
3
−
1
x
3
=
(
x
−
1
x
)
3
+
3
×
x
×
1
x
×
(
x
−
1
x
)
∴
x
3
−
1
x
3
=
(
3
)
3
+
3
×
(
3
)
=
27
+
9
=
36
© examsnet.com
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