Solution:
Given, an isosceles triangle of sum of the two sides =16cm Let the two equal sides be acm and the third be bcm.
We known that, the sum of two sides of a triangle is always greater than the third side.
∴ Possible measurements, when a=8
Then b=1,2,3,.............,15
[total =15 triangles ] and when,
a=6,7,9,10,11,12,13,14,15
Then b=10,9,7,6,5,4,3,2,1 [total 9 triangles]
∴ Total possible triangles =15+9=24
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