Since, the tangent at any point of a circle is perpendicular to the radius through the point of contact. ∴∠PQO=∠PRO=90∘ Since, △PQO and △PRO are right angle triangle ∴PQ=PR=√(15)2−(9)2 =√225−81=12cm. ∴ Area of the quadrilateral PQOR= Area of △PQO+ Area of △PRO ∴ Area of the quadrilateral PQOR =