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SSC CHSL 24-March-2018 Shift 2 Paper
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© examsnet.com
Question : 16
Total: 100
The distance between places U and V is 1008 km. An express train leaves place U at 9:00 a.m. and runs at a speed of 126 km/hr. The train stops on the way for 20 minutes. At what time (in p.m.) the train will reach at the place V?
6 : 50
3 : 50
4 : 20
5 : 20
Validate
Solution:
Distance to be covered = 1008 km and speed of train = 126 km/hr
Using, time = distance/speed
⇒ Time taken =
1008
126
=
8
hours
∴ Train will reach at place V = 9:00 am + 8 hours + 20 minutes = 5 : 20 pm
© examsnet.com
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