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SSC CHSL 5 Aug 2021 Shift 3 Solved Paper
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© examsnet.com
Question : 61
Total: 100
The speed of a train is
78
k
m
∕
h
. If crosses a tunnel in
45
s
e
c
and overtakes a person walking at a speed of
6
k
m
∕
h
, in the same direction, in
15
s
e
c
. The length (in
m
) of the tunnel is
675
650
975
780
Validate
Solution:
Given, speed of train
=
78
k
m
∕
h
=
78
×
5
18
=
195
9
m
∕
s
Speed of person
=
6
k
m
∕
h
=
6
×
5
18
=
5
3
m
∕
s
According to the question,
195
9
−
5
3
=
length of train
15
[
∵
s
=
d
t
]
∴
Length of train
=
20
×
15
=
300
m
let the length of the tunnel be
x
m
.
∴
300
+
x
=
195
9
×
45
=
975
x
=
975
−
300
=
675
m
© examsnet.com
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