SSC CHSL 9-Jan-2017 Shift 3 Paper

Coordinates of A (5,0) , B (-2,3) and C (-1,4). Let coordinates of D = (x,y)
ABCD is a parallelogram and AB is parallel to CD, thus slopes of AB and CD are equal.
⇒

3−0

−2−5

=

4−y

−1−x

⇒ −

3

7

=

4−y

−1−x

⇒ 3+3x=28−7y
⇒ 3x+7y=25 ------(i)
Also, BC is parallel to AD
⇒

3−4

−2+1

=

y−0

x−5

⇒ x−5=y -------(ii)
Substituting value of 'y' in equation (i), we get : 3x+7(x−5)=25
⇒ 3x+7x−35=25
⇒ x=

60

10

=6
Putting it in equation (ii), ⇒ y=6−5=1
Now, equation of line AD with coordinates (5,0) and (6,1)
⇒ (y−0)=

1−0

6−5

(x−5)
⇒ y=x−5