Force exerted by a jet on a stationary inclined flat plate
Let a jet of water, coming out from the, strike an inclined flat plate as shown in figure.
Let,
a = area of cross section of the jet
=v = velocity of jet in the direction of x
θ = angle between the jet and the plane
Then the mass of the water per sec stricking the plate = ρ × av
Fn = Mass of the jet striking per second × [initial velocity of the jet before striking in the direction of
Fn – final velocity of the jet after striking in the direction of
Fn]
Fn = ρav [v sin θ – 0] ρav
2 sinθ
If the force can be resolved into two components, one in the direction of the jet and the other perpendicular to the direction of the flow. Then we have,
Fx=ρav2sin2θ (along the direction of the flow)
Fy=ρav2sinθcosθ (perpendicular to flow)