SSC JE Mechanical Engineering 2017 Set 2 Solved Paper

According to diagram, Hunter goes from A to 5 km, B then from B to 3 km towards C, then from C to 5 km toward D, then from D to 5 km, towards E then from E to 5 km, F.
AF = AB + BE + EF
= AB + CD + EF (∵ BE = CD)
= 5 + 5 + 5 = 15
Hence the hunter 15 km North from the starting position.