Power plant rating = One 700 kW and two 500kW Fuel consumption = 0.25 kg per kWh Plant capacity factor = 40% Maximum capacity = (500 + 500 + 700) = 1700 kW Maximum Energy produced in a day = 1700 kW × 24 h = 40800 kWh Actual energy produced = Plant Capacity Factor × Maximum energy produced in a day Actual energy produced = 0.4 × 40800 kWh = 16320 kWh Fuel oil Required = Fuel consumption × Actual energy produced Fuel oil Required = 16320 × 0.25 = 4080 kg