According to conservation of linear momentum ⇒mv+2m×0=mv1+2mv2‌‌‌⋅⋅⋅⋅⋅⋅⋅(i) ⇒v=v1+2v2 Coefficient of restitution e‌=‌
v2−v1
u1−u2
⇒‌‌e‌‌e‌=‌
v2−v1
v−0
⇒‌‌ev‌=v2−v1 ⇒‌‌v1‌=v2−ev‌‌‌⋅⋅⋅⋅⋅⋅⋅(ii) From Eqs. (i) and (ii), we get ‌v=v2−ev+2v2 ‌v=3v2−ev ‌⇒‌‌v(1+e)=3v2 ‌⇒‌‌v2=‌
v(1+e)
3
‌‌‌⋅⋅⋅⋅⋅⋅⋅(iii) Now, from Eq. (ii) and (iii), we get, v1‌=‌
