Step 1: Find the determinant of A Matrix A is: A=[
1
5
2
4
1
3
2
6
3
] So, |A|=1(3−18)−5(12−6)+2(24−2) Calculate each part: 1×(3−18)=1×(−15)=−15 −5×(12−6)=−5×6=−30 2×(24−2)=2×22=44 Add them up: |A|=−15−30+44=−1 Step 2: Find the value of |(adjA)−1| |(adjA)−1|=
1
|adjA|
The order of matrix A is 3 , so: |adjA|=|A|3−1=|A|2 So, |(adjA)−1|=