The given circle is 5x2−xy−5x+y=0 (x−1)(5x−y)=0 Therefore the centre of the circle is (1,5) The second circle is given by x2+y2−2x+2y−7=0 (x−1)2+(y+1)2=9 The centre of the circle is (1,-1) and radius is 3 Therefore, the equation of the first circle is (x−1)2+(y−5)2=9 x2+y2−2x−10y+17=0 The equation of chord at (1,-1) is x−y−2