The equations of the given curves are y2=4x and x2+y2−6x+1=0 Equation of tangent to the parabola y=mx+
1
m
The above line is also tangent to the circle as well. Therefore, 2√2=|
3m+
1
m
√1+m2
| 8(1+m2)=9m2+
1
m2
+6 m4−2m2+1=0 m=±1 Therefore, the equations of the common tangents are y=x+1,quady=−x−1 Both the statements are true and (R) is correct explanation of (A)