Consider the equation, x3−6x2+px+10=0 Now, α,β,γ are in A.P and are roots of the above equation so, α+β+γ=6.......(I) αβ+βγ+γα=p.......(II) αβγ=−10.......(III) since, α+γ=2β then from equation (I) 3β=6 β=2 Substitute 2 for β in equation (III), αγ=−5 Then from equation (II), β(α+γ)+γα=p 2β2+β=p p=8−5 =3 Now consider α3+β3+γ3−3αβγ=(α+β+γ)[