The expression for the depression of freezing point is, ∆Tf=iKfm Consider the molality, m‌‌=‌
W
M
×‌
1000
V
‌‌=‌
0.1
329
×‌
1000
100
‌‌=0.003039 So, the depressionof freezing point is, ∆Tf=4(1.86)(0.003039) =0.02261 since, T0‌‌=273K ‌‌=0∘C Then, ∆Tf‌‌=T0−Tf 0.02261‌‌=0−Tf Tf‌‌=0.026∘C