Consider the integral, I=∫sec5dx Simplify the above, I=∫sec3xsec2xdx=sec3xtanx−∫3sec3xtan2xdx=sec3xtanx−3∫sec3x(1+sec2x)dx=sec3xtanx−3∫sec5xdx−3∫sec3xdx Further simplify the above, I=sec3xtanx−3I−3∫sec2x1+tan2xdx Take tanx=t then 4I=sec3xtanx−3∫t2+1dx4I=sec3xtanx−23t1+t2+23log∣t+1+t2∣+cI=4sec3xtanx−83secxtanx+83log∣secx+tanx∣+c=4(sec2x)secxtanx+83secxtanx+83log∣secx+tanx∣+c Further simplify I=4(1+tan2x)secxtanx+83secxtanx+83log∣secx+tanx∣+c=4secxtan3x+85secxtanx+83log∣secx+tanx∣+c