Consider the reaction shown below, H2SO4⇌2H++SO42− The concentration of H+ is calculated as H+=2×0.001M =0.002M The pH is calculated as, pH=−log[H+] =−log(0.002) =2.69 The pOH is calculated as pH+pOH=14 pOH=14−pH pOH=14−2.69 pOH=11.31 The [OH] concentration is calculated as, pOH=−log[OH−] 11.31=−log[OH−] [OH−]=5×10−12