Consider the equation. sinh−1(√8)+sinh−1(√24)=α Let sinh−1(√8)=x sinhx=√8 So, cos(hx)=√1+8 =3 And sinh−1(√24)=y sinhy=√24 So coshy=√1+24 =5 Also sinh(x+y)=sinhxcoshy+sinhycoshx =5√8+3√24 =10√2+6√6 x+y=sinh−1(10√2+6√6) α=sinh−1(10√2+6√6) sinh(α)=10√2+6√6