A line L passing through i+2j−3k and parallel to vector √2i−5j+3k is r=i+2j−3k+λ(√2i−5j+3k) Let any point P lie on line is (√2λ+1,−5λ+2,3λ−3) And A=i+2j−3k It is given that PA=18 Therefore, (√2λ+1−1)2+(−5λ+2−2)2+(3λ−3+3)2=182 2λ2+25λ2+9λ2=182 λ2=
182
36
λ=3,−3 Thus P=(3√2+1)−−13j+6k Or P=(1−3√2)i+17j−12k