Let the probability of having error in X is, P(E1)=0.1 Let the probability of having error in Y is, P(E2)=0.3 The events are independent. Thus, P(E1∩E2)=P(E1)P(E2) =0.03 The required probability is calculated as, P=(0.07×0.5)+(0.27×0.7)+(0.03×0.8) =