Given, Ionic product of Ca(OH)2=5.5×10−6 Concentration of NaOH solution =010M ∴Ionic product of Ca(OH)2=5.5×10−6 or, Ca(OH)2=[Ca2+]+2[OH−] Let, solubility =S Ca2++2[OH−]\S(2S)2 Also, Ksp =4S3 where, Ksp= solubility product ∴ Due to common ion effect, Molar solubility of Ca(OH)2=
5.5×10−6
0.1×0.i
=5.5×10−4 Hence, option (c) is the correct answer.