∵H2O2 show oxidising as well as reducing action. Oxidising nature (i.e. act as oxidising agent) (i) In acidic solution, H2O2+2H++2e−⟶2H2O (ii) In alkaline solution, H2O2+2e−⟶2OH− Reducing nature (i.e. act as reducing agent)
H2O2
(inacidicmedium)
⟶2H++O2+2e−
H2O2+2OH−
(inalkalinemedium)
⟶2H2O+O2+2e− Hence, (i), (ii), (iii) and (iv) all are possible and (c) is the correct answer.