Given, Vapour pressure of pure water =23mmHg10% of solute A Molecular weight of A=50 Mass of A=10g Mass of water =100−10=90g Number of moles of A=‌
10
50
=0.2 Number of moles of water =‌
90
18
=5 ∴ Total number of moles =5+0.2=52 Mole fraction of solvent =‌