TS EAMCET 11-Sep-2020 Shift 2 Solved Paper

Given, frequency heard by first truck driver,
v=495Hz
Velocity of sound, vs=u
Velocity of trucks, v1=v2=0.1u
In the first case, when two trucks are approaching each other:
The frequency heard by second truck driver,
=‌

1.1

0.9

×495=605Hz
In the second case, when two trucks are receding each other:
The frequency heard by second truck driver,
=‌

0.9

1.1

×495=405Hz
v1−v2=605−405=200Hz