∵ (i) Sodium acetate, i.e. (CH3COONa) in water gives CH3COOH and NaOH as follows:
CH3COONa+H2O⇌CH3COOH+NaOH
Hence, for (i) pH>7. [ ∵ solution is basic] Also, (ii) when, ammonium chloride, i.e. (NH4Cl ) is added in water, it gives NH4+ (aqueous) and Cl− (aqueous) ions.
NH4+ (aqueous) +H2O⟶NH3+H++OH−
Hence, pH<7 Hence (a) is the correct answer, i.e. for (i) pH>7 and for (ii) pH<7.