Given, x2−3|x|+2=0 (|x|−2)(|x|−1)=0 |x|=2 or |x|=1 x=±2 or x=±1 and y2−3y+2=0 (y−2)(y−1)=0 ⇒y=2,1
Equation of diagonal are B′D′=x−y=0 Equation of diagonal A′C′=x+y=3 Equation of diagonal AC=x+y=0 Equation of diagonal BD=x−y+3=0 Ist square, x+y=3,x−y+3=0 IInd square, x+y=0,x−y=0