3+ix+i(x−2)​−i=i−32y+i(1−3y)​⇒3+ix+(x−2)i​+3−i2y+(1−3y)i​=i⇒(3+i)(3−i){(4x−2)+i(2x−6)}+{(9y−1)+i(3−7y)}​=i⇒(4x+9y−3)+i(2x−7y−3)=0+10iOn comparing the real and imaginary parts 4x+9y−3=0 and 2x−7y−3=10⇒4x+9y=3⋯(i)2x−7y=13⋯(ii)On subtracting Eq. (ii) ×2 from Eq. (i), 4x+9y=34x−14y=2623y=−23y=−1From Eq. (i), x=3∴x+y=2