The roots of the given equations are √3+√2 and √3−√2 ∴x=√3+√2i⇒x−√3=√2i ⇒(x−√3)2=(√2)2⇒x2+3−2√3x=−2 ⇒x2+5=2√3x⇒(x2+9)2=(2√3x)2 ⇒x4+25+10x2=12x2⇒x4−2x2+25=0 Also, x=√3−√2 ⇒x2=(√3−√2)2⇒x2=3+2−2√6 ⇒x2−5=−2√6⇒(x2−9)2=(−2√6)2 ⇒x4+25−10x2=24⇒x4−10x2+1=0 ∴ The required equation is (x4−2x2+29(x4−10x2+1)=0.