Hydrolysis of XeF4 will give XeO3 and Xe along with HF and O2. It is a type of disproportionation. reaction in which XeF4 undergoes oxidation as well as reduction.
6XeF4+12H2O→4‌Xe+2XeO3+24‌HF+3O2
∴‌‌a=6 ‌b=12 ‌p=4 q‌=2 ‌r=24 and ‌s=3