Balanced chemical equation can be given as ‌Fe3O4+4‌CO→3‌Fe+4CO2 ‌1‌mol‌of‌Fe3‌O4(232g)=3mole Fe(168g) [Molecular mass of Fe3O4=232g‌ ] ‌ Amount of Fe3O4 required for kg} iron ‌=‌
232×1000‌kg
168×1000‌kg
×4=5.52‌kg Since, efficiency of reaction is 80%. Hence, actual required amount of Fe3O4 will be =‌