The required equation of plane passes through the points (1, -1, 6), ( 0, 0, 7) and perpendicular to the plane x - 2y + z = 6 is calculated as, |
x−1
y+1
z−6
0−1
0+1
7−6
1
−2
1
|=0 |
x−1
y+1
z−6
−1
1
1
1
−2
1
|=0 (x−1)(1+2)−(y+1)(−1−1)+(z−6)(2−1)=0 3x+2y+z−7=0 The point (1,1,2) satisfy the above equation. Thus, the planepasses through this point.