Given, initial, final pressure and temperature of surrounding pi,pf and Ti,Tf. We know that, adiabatic relation between p and T is given as p1−γTγ= constant where, γ is adiabatic constant =3∕2 Therefore, pi1−γ⋅Tiγ=pf1−γ⋅Tiγ ⇒21−3∕2⋅T3∕2=11−3∕2Tf3∕2(∵pi=2atm,Ti=T) ⇒2−1∕2T3∕2=1−1∕2Tf3∕2 ⇒Tf3∕2=