Given, initial pressure, pi=105Pa Initial temperature, Ti=20∘C Final temperature, Tf=127∘C Coefficient of linear expansion, α=10−5C−1 Bulk modulus of metal, B=2×1011N∕m2 As we know that, B=‌
−p
∆V∕V
where, ∆V∕V is volumetric strain. ⇒‌‌p=B‌
∆V
V
. . . (i) and since ‌
∆V
V
=γ∆T put in Eq. (i), we get where, γ= volumetric expansion. ∴‌‌‌‌=Bγ∆T ‌‌=B3α∆T ‌‌=2×1011×3×10−5(127−20) ‌‌=6×106(107)=642×106 ‌‌=6.42×108N∕m2 ‌∼eq6×108Pa