The reaction is as follows: N2+3H2 → 2NH3 Let us make an I.C.E table as shown below.
N2
+
3H2
⇌
2NH3
Initial
1
1
0
Change
x
3x
2x
Equilibrium
1−x
1−3x
1−2x
The value of x can be calculated as follows: 1−x=0.7mol x=0.3mol The concentration of the species can be calculated as shown below. [N2]=0.7 [H2]=1−(3×0.3)=0.1 [NH3]=1+(2×0.3)=1.6 Now the equilibrium constant can be calculated as follows. Kc=