The points in Cartesian form are,
(2,1,1),(-1,-1,1) and (-1,1,-1)
The equation of plane passing through three points is,
|| =0 Solve the above determinat then,
2x−y−3z=0 The above equation can be expressed in vector form as,
r.(2−−3)=0 If e is unit vector perpendicular to given plane then,
e= =(2−−3) And,
a=2−3+6 The projection of a on e is calculated as,
a.e=+− = The projection vector of a on e is calculated as,
a.e=−((2−−3)) = (−2++3)